If the diameter of a soap bubble is 10mm

Asked by admin @ 17/08/2021 in Physics viewed by 300 People

If the diameter of a soap bubble is 10 mm and its surface tension is 0.04 N m⁻¹, find the excess pressure inside the bubble.

Answered by admin @ 17/08/2021

Excess pressure inside the soap bubble is given by, $P=\frac{4S}{r}$

where S is surface tension of soap bubble ,
r is the radius of the soap.

given, surface tension of soap bubble, S = 0.04 N/m
diameter of soap bubble, d = 10mm
radius of soap bubble , r = 5mm = 5 × 10^-3 m

now, excess pressure inside the soap bubble , P = 4 × 0.04/5 × 10^-3

P = 4 × 0.04/0.005 = 160/5 = 32 N/m²

hence, excess pressure inside bubble is 32 N/m².

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