Pressure inside two soap bubbles are 1.02 and 1.05
Asked by admin @ in Physics viewed by 310 People
Pressure inside two soap bubbles is 1.02 atm and 1.05 respectively. The ratio of their surface area is
Answered by admin @
The answer is 6.25 : 1
Solution
P = 4S/r , where P=excess pressure inside soap bubble, S -= surface tension, r = radius of bubble. Assuming ambient pressure = 1 atm,
P1/P2 = 0.02/0.05 = (4S/R1)/4S/R2= R2/R/1
P1/P2 = 0.4 = R2/R1
So R1/R2 = 1/0.4 = 2.5 to1
Surface area =4pir^2
4piR1^2/4piR2^2 = R1^2/R2^2 = (2.5/1)^2 = 6.25 to 1
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