Two soap bubbles of radii r1 and r2
Asked by admin @ in Physics viewed by 345 People
two soap bubbles with radii r1 and r2 (r1>r2) come in contact. their common surface has a radius of curvature r=
Answered by admin @
Hey buddy,
◆ Answer-
r = r1.r2/(r1-r2)
◆ Explaination-
Lets consider, two soap bubbles with radius r1 nad r2 such that r1 > r2 .
For bubble 1 -
P1 - P0 = 4T/r1
P1 = P0 + 4T/r1 ...(1)
For bubble 2 -
P2 - P0 = 4T/r2
P2 = P0 + 4T/r2 ...(2)
Let's, consider two bubbles merge so that-
P2 - P1 = 4T/r
P0 + 4T/r2 - P0 + 4T/r1 = 4T/r
4T (1/r2 - 1/r1) = 4T/r
1/r = 1/r2 - 1/r1
r = r1.r2 / (r1-r2)
Radius of the common bubble is r1.r2/(r1-r2).
Hope this helps you...
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