Two resistors r1 and r2 are connected in parallel

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when two resistors of resistance R1 and R2 they are connected in parallel the net resistance is 3 ohm when they are connected in series the value 16 ohm calculate R1 and R2

Answered by admin @


Hi
I will answer this
 Resistance equivalent in parallel is given by R1 *R2 / (R1+R2)
Resistance equivalent in series is R1 + R2 
Given R1 + R2 = 16
and R eq in parallel as 3
sustitute the above values in the first equation of parallel equivalence 
we get R1*R2 = 3*16 = 48
The values of R1 and R2 are 12,4
By using basic calculations of (R1-R2)^2 = (R1 +R2)^2 - 4R1R2 
R1 - R2 = sqrt(256-192) = sqrt(64) = 8
solving R1 and R2 we get r1 =12 and r2 =4

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