Two parallel and opposite forces each of magnitude 4000n

Asked by admin @ 20/08/2021 in Physics viewed by 320 People

Two parallel and opposite forces each 4000 newton applied tangentially to the upper and lower faces of a cubical metal block 25 cm on a side find the angle of shear of the upper surface related to the lower surface the shear modulus for the metal is 80 gpa

Answered by admin @ 20/08/2021

Given Two parallel and opposite forces each 4000 newton applied tangentially to the upper and lower faces of a cubical metal block 25 cm on a side find the angle of shear of the upper surface related to the lower surface the shear modulus for the metal is 80 gpa

We are given

Force = 4000 N, metal L = 0.25 m , A = 0.0625 sq m. G = 8 x 10^10 N/m^2

Angle of shear = F / AG

= 4000 / 0.0625 x 8 x 10^10

= 8000 x 10 ^-10

= 8 x 10 ^- 7

We know that

Δ L = Ф x L

= 8 x 10 ^-7 x 0.25

Δ L = 2 x 10^-7 m

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