Y tan 1 3x x 3 1 3x 2
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Question 10: Find dy/dx : y = tan¯¹(3x - x³/1-3x²),-1/√3 < x < √3
Class 12 - Math - Continuity and Differentiability
Answered by admin @
Refer to the attachment
________________
Formulas used ;-
•d/dx(tan-¹x) = 1/1+x²
•tan3∅ = (3tan∅ - tan³∅)/1-3tan²∅
_______________
After putting ∅ = tan-¹x
differentiate w.r.t x
we get
dy/dx = 3/1+x²
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