Y 1 6 x 2

Asked by maham237 @ in Mathematics viewed by 307 People

If the equation y = 1/6(x + 12) were graphed in the xy-plane, which of the following statements would be true of the graphed line?
A. It would be perpendicular to the graph of y = 1/6x + 3.

B. It would be parallel to the graph of 12y = 2x + 3.

C. It would have the same slope as the graph of x + 6y = 18.

D. It would have the same y‑intercept as the graph of y = 1/6x + 12.

Answered by maham237 @


Hi!

The answer B. It would be parallel to the graph of 12y = 2x + 3 is true because the slope of both 12y = 2x + 3 and y= \frac{1}{6} (x + 12) is \frac{1}{6} which means that they run the same direction on a graph and the y-interscept for 12y = 2x + 3 is (0, \frac{1}{4} ) and the y-interscept for y= \frac{1}{6} (x + 12) is (0,2). See graph below:

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