2x 1 3 3x 2 4 2 x 5


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Solve the given inequality for real x: (2x-1)/3 ≥ (3x-2)/4 - (2-x)/5

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Given :   (2x-1)/3 ≥ (3x-2)/4 - (2-x)/5  

To find :  Value of x for real x

Solution:

(2x-1)/3 ≥ (3x-2)/4 - (2-x)/5

multiplying both sides by 60

=> 20(2x - 1) ≥  15(3x - 2) - 12(2- x)

=> 40x - 20  ≥ 45x - 30 - 24 + 12x

=> 40x - 20  ≥ 57x - 54

Adding 54 both sides

=> 40x + 34 ≥ 57x

subtracting 40x on both sides

=> 34 ≥ 17x

Dividing 17 on both sides

=> 2  ≥  x

=> x ≤ 2

x ∈ ( -∞ , 2 ]

x ∈ ( -∞ , 2 ]

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