X 2 3 y 2 3 a 2 3
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If x^2/3 + y^2/3 =2 ,find dy/dx at (1,1)
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Answer:
Step-by-step explanation:
x^2/3 +y^2/3=2
differentiating both sides w.r.t x
d/dx(x^2/3 +y^2/3)=d/dx(2)
2/3 x^-1/3 + (2/3 y^-1/3) dy/dx=0
(2/3 y^-1/3) dy/dx= -2/3 x^-1/3
dy/dx=(-2/3 x^-1/3)/(2/3 y^-1/3)
dy/dx= (- y^1/3 ) / ( x^1/3)
dy/dx (1,1)= -(1)^1/3/ 1()^1/3
dy/dx(1,1)= -1 (answer)
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