Two point charges q1 and q2 are 3m apart
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Two point charges Q1 and Q2 are 3m apart and the sum of charges is 10C. then find the values of Q1 and Q2
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Explanation:
We know that,
According to coulomb's law,the magnitude of the force of attraction or repulsion between two point charges is directly proportional to the product of magnitude of the charges and inversely proportional to the square of the distance between them.. Therefore
F = k Q1Q2/r^2
Therefore, Q1Q2 = Fr^2/ k
Q1Q2 = 0.075 * 3^2/8.99*10^9
Q1Q2 = 7.5 * 10^-11
Now,
According to d condition,
Q1 + Q2 = 20 * 10^ (-6)
Put it in equation 1 after solving we get d value of Q1 which is equal to 5 * 10^ (-6) C
And similarly,Q2 will be 15 *10^ (-6)C
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