Two point charges of 20 microcoulomb and 80 microcoulomb

Asked by admin @ 20/08/2021 in Physics viewed by 362 People

Two point charges 20 microcoulomb and 80 microcoulomb are 10 cm apart at which point on the line joining them electric field will be zero

Answered by admin @ 20/08/2021

Answer:

The electric field will be zero at 6.67 cm distance from 80 micro coulomb.

Explanation:

Given that,

First charge $q_{1}=20\times10^{-6}$

Second charge $q_{2}=80\times10^{-6}$

Distance $d = 10\ cm$

Let the electric field will be zero at point O.

Two point charges 20 micro coulomb and 80 micro coulomb are 10 cm apart at point A and B.

The distance between O and A is (10-x) cm and the distance between O and B is x cm.

Since,

$E_{A}=E_{B}$

$\dfrac{k\ 20\times10^{-6}}{(10-x)^2}=\dfrac{k\ 80\times10^{-6}}{x^2}$

$20\times10^{-6}\times x^2=(10-x)^2\times80\times10^{-6}$

$x^2=4(10-x)^2$

$x= 6.67 cm$

Hence, The electric field will be zero at 6.67 cm distance from 80 micro coulomb.

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