The velocity and acceleration vectors of a particle undergoing

Asked by admin @ 20/08/2021 in Physics viewed by 250 People

The velocity and acceleration vectors of a particle undergoing circular motion are v =2i^ m/s and a =2i^+4j^m/s2 respectively at an instant of time. The radius of the circle is

Answered by admin @ 20/08/2021

linear velocity of particle in a circle , v = 2i m/s

acceleration of particle in the circle, a = (2i + 4j) m/s²

concept : in circular motion, acceleration of particle should be perpendicular to its velocity.

it is possible when we take vertical component of acceleration i.e., (4j)

[ because we know, unit vector, i is perpendicular upon j. so, 2i will perpendicular upon 4j]

so, |a| = 4, |v| = 2

now, radius of circle, r = |v|²/|a|

= 2²/4 = 4/4 = 1m

hence, radius of circle is 1m

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