Escape velocity of an atmospheric particle which is 1000km

Asked by admin @ 13/08/2021 in Physics viewed by 312 People

Escape velocity of an atmospheric particle which is 1000km above the earth's surface, is (radius of earth is 6400km and g=9.8m/s2

Answered by admin @ 13/08/2021

Escape velocity on surface of earth is
v = sqrt(2GM / R) = 11.2 km/s ……[2]

Escape velocity at height h is
v’ = sqrt[2GM / (R + h)] ……[1]

Divide equations [1] and [2]
v / v’ = sqrt[(R + h) / R)]
11.2 / v’ = sqrt[(6400 + 1000) / 6400]
v’ = 11.2 / 1.075
v’ = 10.4 km/s

Escape velocity at that height is 10.4 km/s

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