A particle moves with a velocity 5i 3j 6k


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a particle moves with a velocity v=5i-3j+6k m/s- under the influence of a constant force F=10i+10j+20k N .The instantaneous power applied to the particle is. a)200j-s– b)40 j-s– c)140j-s– d)170j-s–​

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Answer:

Option (c)140J-s

power(P)=F.v

=(10i+10j+20k).(5i-3j+6k)

=10*5-10*3+6*20=50-30+120=140j-s


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