The electric flux for gaussian surface a that encloses
Asked by admin @ in Physics viewed by 419 People
The electric flux for Gaussian surface A that enclose the charged particles in free space is
(Given q1 = -14 nC, q2 = 78.85 nC, q3 = – 56 nC)
Answered by admin @
We have to find the electric flux for Gaussian surface A that enclose the charge particles in free space.
(Given, q₁ = -14 nC , q₂ = 78.85 nC and q₃ = - 56nC )
Solution : from Gauss’ law, electric flux is the ratio of charge enclosed inside the surface to the permittivity of medium.
i.e., Φ = q/∈₀
see figure, it is clear that total charge enclosed inside the Gaussian surface A = q₁ + q₂ + q₃
= -14nC + 78.85 nC - 56nC
= 8.85 nC
= 8.85 × 10^-9 C
Now, Φ = (8.85 × 10^-9)/(8.85 × 10^-12)
= 10³ Nm²/C
Therefore electric flux for Gaussian surface A is 10³ Nm²/C
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