A spherical gaussian surface encloses a charge of 8.85

Asked by admin @ 17/08/2021 in Physics viewed by 322 People

A spherical Gaussian surface encloses a charge of 8.85  1010 C. (i) Calculate the

electric flux passing through the surface (ii) How would the flux change if the radius
of the Gaussian surface is doubled and why?

Answered by admin @ 17/08/2021

Using Gauss law: integral E . dS = q/ε
Flux = 8.85 * 10^-10 /ε units.

If the radius is doubled for the spherical surface still the flux remains same, as that depends only on the charge enclosed..... in other words, electric field reduces and radius increases, E * R^2 remains same.

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The electric flux for gaussian surface a that encloses

Asked by admin @ 17/08/2021 in Physics viewed by 418 persons

The electric flux for Gaussian surface A that enclose the charged particles in free space is (Given q1 = -14 nC, q2 = 78.85 nC, q3 = – 56 nC)

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