A particle moves a distance x in time t

Asked by admin @ 11/08/2021 in Physics viewed by 311 People

A particle moves a distance x in time t according to equation x=(t+5)^minus 1. The acc of particle is proportional to

Answered by admin @ 11/08/2021

Distance x=(t+5)−1x=(t+5)−1

velocity v=dxdtv=dxdt=−(t+5)−2=−(t+5)−2

acceleration a=dvdta=dvdt=2(t+5)−3=2(t+5)−3

Therefore v3/2=−(t+5)−3v3/2=−(t+5)−3

Therefore a=−2v3/2a=−2v3/2

aαv3/2aαv3/2

Hence a is the correct answer.

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Asked by admin @ 16/08/2021 in Physics viewed by 307 persons

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