A particle moving along x axis has acceleration f

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A particle moving along x-axis has acceleration f at time t given by f=fo(1-t/T), where fo and T are constants.The particle at t=0 has zero velocity.In time interval between t=0 and the instant when f=0, the particle's velocity (Vx) is?

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Instantaneous velocity at the instant when t = 0, a = ao(1 - t/T), When a = 0, t = T, a = ao(1 - t/T), dv/dt = ao(1 - t/T), dv = ao(1 - t/T) dt,


Integrate, v = ao(t - t²/(2T)), When t = T (i.e when a = 0), v = ao(T - T²/(2T)), v = ao(T/2). Therefore, velocity at the instant when a = 0 is = ao(T/2)


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