The position x of a particle varies with time

Asked by admin @ 11/08/2021 in Physics viewed by 314 People

The position x of a particle varies with time to as x= at square - bt cube. The acceleration of the particle will be zero at time t equal to

1) a/b 2) 2a/3b 3) a/3b 4) zero

Answered by admin @ 11/08/2021

X = at² - bt³

acceleration means change in velocity per unit time . e.g a = dv/dt .
and we also know, velocity is change in displacement per unit time .e.g v = dx/dt

hence, acceleration = d²x/dt²

now, differentiate x = at² - bt³ with respect to t

dx/dt = 2at - 3bt²

again, differentiate with respect to t
d²x/dt² = 2a - 6bt

according to above we know, d²x/dt² is acceleration so,
acceleration = 2a - 6bt
but question ask acceleration is zero in which time . so,
2a - 6bt = 0

6bt = 2a

t = a/3b

hence, option (3) is correct .

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