Answer:
Explanation: In this problem we will have a mass m strike another mass of 4m in a head on collision. This will be found out as elastic or inelastic collision depending upon the e or coefficient of restitution value. If it is 1 it's elastic or otherwise inelastic if ranges from 0 to 1.
Now as we know that momentum is conserved and the masses of the object will remain same before and after collision.
We have the formula as
MaVia + MbVib = MaVfa + MbVfb
Ma and Mb are masses given as m and 4m
Via and Vib are inital velocities of a and by which is v and 0 respectively (object at rest)
Vfa and Vfb are 0(comes to rest) and to be found out respectively
We will have in simplified way ,
MaVia = MbVfb
Putting values
mv = 4mVfb
Vfb= v/4= 0.25v
Now coefficient of restitution will be
e= (Vfa - Vfb) /( Vib - Via)
= -0.25v/-v
= 0.25