A block of mass 10 kg moving with acceleration

Asked by admin @ 23/08/2021 in Physics viewed by 464 People

43. A block of mass 10 kg, moving with acceleration 2 m/s2 on horizontal rough surface is shown in figure

→ a= 2 m/s> F= 40 NThe value of coefficient of kinetic friction is(1) 0.2(3) 0.5(2) 0.4(4) 0.1

Answered by admin @ 23/08/2021

Answer:

(i)0.2=coefficient of kinetic friction

Explanation:

formula: [f(k)= μk N]

so, we first have to find the value of N and fk to solve the problem:--

N=mg=10*10=100 [taking g=10m/s²]-------------(i)

now, force=mass*a

F-fk=ma

40-fk= 10*2

40-fk=20

-fk=20-40

-fk=-20

fk=20 ---------------(ii)

substitute value of (i) and (ii) in the formula:

we get,

μk=fk/N

= 20/100

= 0.2

Hope It Helps You..

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