Assuming the mass of an average cell is ten times the mass of a bacterium (which is 10-15 kg):

Asked by maham237 @ 26/12/2020 in Biology viewed by 429 People

(a) Calculate the number of cells in a hummingbird assuming the mass of an average cell is ten times the mass of a bacterium.
(b) Making the same assumption, how many cells are there in a human?

Answered by maham237 @ 26/12/2020

Given :

Average mass of the cell = 10 X mass of bacterium.

Number of cell= (Mass of humming bird)/ (mass of the [email protected])

a) The mass of a hummingbird is , while the mass of a cell is . The number of cells in the hummingbird is

〖10〗^(-2)/〖10 X 10〗^(-15) = 〖10〗^12 cells

Number of cells in humming bird = 1012 cells

b) The mass of a person is .

(〖10〗^2 kg)/(10 X 〖10〗^(-15) )= 〖10〗^16 cells

Number of cells in human = 1016 cells

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