Y cos x 2
Asked by maham237 @ in Mathematics viewed by 312 People
Implicit differentiation: ycosx=x^2+y^2
Derivative of both sides:
=((y)(-sinx)+(cosx)(dy/dx)=2x+2y(dy/dx)
=(-ysinx+cosx(dy/dx)=2x+2y(dy/dx)
=cosx(dy/dx) - 2y(dy/dx) = ysinx+2x
=(cosx-2y)dy/dx = ysinx+2x
=dy/dx = (ysinx+2x)/(cosx-2y)