Given the geometric sequence where a1 = 4 and the common ratio is 3, what is the domain for n?


Asked by maham237 @ in Mathematics viewed by 375 People


Given the geometric sequence where a1 = 4 and the common ratio is 3, what is the domain for n?
All integers where n ≥ 1

All integers where > 1

All integers where n ≥ 4

All real numbers
For this its always greater than one right? for every type of these things?

also Given the arithmetic sequence an = 4 − 3(n − 1), what is the domain for n?

All integers where n ≥ 1

All integers where n > 1

All integers where n ≤ 4

All integers where n ≥ 4

Answered by maham237 @



Since r is greater than 1, that means integers greater than or equal to 1.
It can't be all real numbers, because that would include negative number.

If the starting number of a sequence is 4, if we put n=0, then we get 4, but if we put in a negative n, we would get a value that isn't part of our sequence, so it has to be n is greater than or equal to 1.


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