Identify the 16th term of a geometric sequence where a1 = 4 and a8 = −8,748.

Asked by maham237 @ in Mathematics viewed by 349 People

Identify the 16th term of a geometric sequence where a1 = 4 and a8 = -8,748.. . -172,186,884. -57,395,628. 57,395,628. 172,186,884.

Answered by maham237 @


First, determine the common ratio by the equation,
an = a1 x r^(n - 1)
Substituting the values,
-8748 = 4 x r^(8 - 1)
The value of r is -3. By the same equation, the 16th term is,
a16 = 4 x (-3)^(16 - 1)
a16 = -57,395,628
Thus, the answer is the second choice.

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