Identify the 42nd term of an arithmetic sequence where a1 = −12 and a27 = 66.
Asked by maham237 @ in Mathematics viewed by 318 People
Answered by maham237 @
The arithmetic formula is expressed as an = a1 + d *(n-1)where n is an integer. Substituting from the given a1 = -12 and a27 = 66, 66 = -12 + d *(27-1). hence , d is equal to 3. a42 thus using the formula is equal to 111. The final answer to this problem is 111.
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