Given the geometric sequence where a1 = 3 and the common ratio is -1, what is the domain for n? a. all integers where ≤ 0. b. all integers where n ≥ 0. c. all integers where n ≤ 1. d. all integers where n ≥ 1 . . would the answer be a considering that the ration is a negative?

Asked by maham237 @ 27/12/2020 in Geography viewed by 312 People

Answered by maham237 @ 27/12/2020

Answer:

Option: d is the correct answer.

The domain for n is all the integers where n≥1.

Step-by-step explanation:

We know that a geometric sequence also known as geometric progression in which each term is found by multiplying the preceding term by a constant factor.

That common factor is also known as a common ratio and is denoted by 'r'.

Now, the sequence is given as:

$a_1=a\\\\a_2=ar\\\\a_3=ar^2\\\\a_4=ar^3\\.\\.\\.\\.\\.\\.\\.\\.\\.$

Hence, the nth term of the sequence is given by:

$a_n$ where n belongs to natural numbers.

Where a is the first term of the sequence i.e. when n=1

Hence, the domain for n is:

d. All integers where n ≥ 1

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