Multiply the binomials 2x 5 and 4x 3


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"Question 1 Multiply the binomials. (i) (2x + 5) and (4x − 3) (ii) (y − 8) and (3y − 4) (iii) (2.5l − 0.5m) and (2.5l + 0.5m) (iv) (a + 3b) and (x + 5) (v) (2pq + 3q^2) and (3pq − 2q^2) (vi) 3a^2/4 + 3b^2

Class 8 Algebraic Expressions and Identities Page 148"

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Algebraic expressions:


A combination of constants and variables
connected by any or all of the four fundamental operations +, -,×,÷ is called
an algebraic expression


Multiplication of algebraic expression:


The product of two factors with like signs
is positive and the product of two factors with unlike signs is negative.

Multiplication of a binomial  and the binomial:

 

 Let  ( a+b)&  (c+d) are two Binomials. By using distributive
law of multiplatinum over addition twice, we may find their product



( a+b)× (c+d)

= a(c+d) + b( c+d)

=(a ×  c+a ×  d)+(b ×  c+b × d)

= ac+ad+bc+bd


This
method is known as the horizontal method.

=========================================================

Solution:

i)

(2x + 5)(4x - 3)

2x(4x - 3)+ 5 (4x-3)

= 2x x 4x - 2x x 3
+ 5 x 4x - 5 x 3



= 8x² - 6x + 20x -15


= 8x² + 14x -15



ii) ( y - 8)(3y - 4)

y(3y - 4)-8(3y - 4)

= y x 3y - 4y - 8 x 3y + 32



= 3y² - 4y - 24y + 32


= 3y² - 28y + 32



iii) (2.5l - 0.5m)(2.5l + 0.5m)

 

2.5l (2.5l + 0.5m) -0.5m(2.5l + 0.5m)

= 2.5l × 2.5l + 2.5l ×0.5m -0.5m× 2.5l + 0.5m× 0.5m

= 6.25l² +1.25lm – 1.25lm + 0.25n²


= 6.25l² - 0.25m²



iv)( a+3b)(x+5)

a(x+5)+3b(x+5)

ax + 5a + 3b x + 15b



v) (2pq+3q²)(3pq-2q²)

2pq(3pq-2q²) + 3q²(3pq-2q²)

2pq x 3pq - 2pq x 2q² + 3q²x 3pq
- 3q2 x 2q²



= 6p²q² - 4pq³ + 9pq³- 6q⁴

 = 6p²q² + 5pq³ - 6p⁴

 

vi) ( 3a²/4+3b²)(4(a² -2b²/3))

( 3a²/4+3b²)(4a² -8b²/3)

=3a²/4((4a² -8b²/3)+ 3b²(4a² -8b²/3)

= 3a⁴-2a²b²+12a²b²-8b⁴


= 3a⁴+10a²b²-8b⁴

==========================================================

Hope this will help you....


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