Find two consecutive positive integers whose sum is 365


Asked by admin @ in Math viewed by 357 People


Find two consecutive positive integers, sum whose squares is 365.

Answered by admin @



let the no. be  x and x+1
  then we have x²+(x+1)²=365
                     2x²+2x-364=0
                     x²+x-182=0
                     x²+14x-13x-182=0
                     (x+14)(x-13)=0
                 That gives x=13 Avoiding negative value
                 one number is 13 and other one 14.

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