Find two consecutive positive integers whose square is 365

Asked by admin @ 20/08/2021 in Math viewed by 304 People

Find two consecutive positive integers, sum whose squares is 365.

Answered by admin @ 20/08/2021

let the no. be x and x+1
then we have x²+(x+1)²=365
   2x²+2x-364=0
   x²+x-182=0
   x²+14x-13x-182=0
   (x+14)(x-13)=0
   That gives x=13 Avoiding negative value
   one number is 13 and other one 14.

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