Find all pairs of consecutive even positive integers


Asked by admin @ in Math viewed by 294 People


Question 24 Find all pairs of consecutive even positive integers, both of which are larger than 5 such that their sum is less than 23.

Class X1 - Maths -Linear Inequalities Page 122

Answered by admin @



Let 2x and 2x +2 are two consecutive even positive integers .
Then a/C to question,
2x > 5 => x> 5/2

and 2x + 2 > 5
=> 2x > 5-2 = 3
=> 2x > 3
=> x> 3/2

and , sum of 2x and 2x +2 < 23
2x + 2x +2 < 23
=> 4x < 23 -2
=> 4x < 21
=> x < 21/4
now plotting these all value on number line , ( see attachment )
from attachment , its clear that
5/2 < x < 21/4
hence, possible value of x = 3, 4, 5
so, when x = 3 then, (2×3,2×3+2) = (6,8)
when x = 4 then , (2×4,2×4+2) = (8,10)
when x= 4 then , (2×5,2×5+2) = (10,12)
hence, required pair (6,8) , (8,10) and (10,12)

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