Given : A box contains 4 red balls and 6 black balls.
Three balls are selected randomly from the box one after another, without replacement.
To Find : The probability that the selected set contains one red ball and two black balls is
Solution:
Red = 4
Black = 6
Total = 10
3 out of 10 can be selected in ¹⁰C₃ = 120
set contains one red ball and two black balls
Number of ways
⁴C₁*⁶C₂
= 4 * 15
= 60
probability that the selected set contains one red ball and two black balls is = 60/120
= 1/2
= 0.5
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