Given:
Number of white balls in the box = 2
Number of black balls in the box = 3
Number of red balls in the boc = 5
To find:
Number of ways in which 3 balls can be drawn from the box if at least one black ball is to be included in the draw.
Solution:
If at least one black ball is to be included in the draw then there woule 3 possibilities:
- Exactly one black and 2 non-black balls = 3C1 × 7C2
- Exactly 2 black and 1 non-black balls = 3C2 × 7C1
- Exactly 3 black and 0 non-black balls = 3C3 × 7C0
Hence the total number of possibilities will be:
3C1 × 7C2 + 3C2 × 7C1 + 3C3 × 7C0
= 85
Thus the correct option is D i.e. 85.