While measuring acceleration due to gravity by a simple pendulum

Asked by admin @ 02/08/2021 in Physics viewed by 281 People

while measuring acceleration due to gravity by a simple pendulum a student make a positive error of 1% in the length of the pendulum and negative error of 3% in the value of the time period is percentage error in the measurement of the value of Gram will be

Answered by admin @ 02/08/2021

we know,
   time period is given by T = $\bold{2\pi\sqrt{\frac{l}{g}}}$
for finding error in case of g is given by
Δg/g = Δl/l + 2ΔT/T
⇒ Δg/g × 100 = Δl/l × 100 + 2 × ΔT/T × 100
⇒ % error in g = % error in l + 2 × % error in T
⇒ % error in g = 1 % + 2 × 3 %
   = 1% + 6%
   = 7%
hence the error in measurement of value of g is 7%

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