Four particles of masses m 2m 3m and 4m
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four particles of masses m, 2m, 3m, 4m respectively are placed at the corners of a square of side a, as shown in fig
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Answer:
Answer
Let co-ordinates of center of mass is M(x,y).
x=
m
1
+m
2
+m
3
+m
4
m
1
x
1
+m
2
x
2
+m
3
x
3
+m
4
x
4
=
m+4m+3m+2m
m×0+(4×0+3×a+2×a)m
=
10m
5am
=
2
1
a
y=
10m
m×0+4m×a+3m×a+2m×0
=
10m
7am
=
10
7
a
M(
2
1
a,
10
7
a)
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