A charged particle of mass m and charge q


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A charged particle of mass m and charge q initially at rest is released in an electric field of magnitude E . It's kinetic energy after time t will be ??

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Answer:

Given:

Mass of charged particle = m

Charge = q

Electric Field Intensity = E

To find:

Kinetic energy after time t

Concept:

In presence of the Electric Field, the charge will experience a force. This force will provide acceleration leading to increase in speed of the particle.

Calculation:

∴ Force experienced = charge × Field

=> Force = q × E

=> Force = qE

∴ Acceleration = Force/mass

=> a = (qE)/m

Applying equation of motion :

∴ v = u + at

=> v = 0 + {(qE)/m}t

=> v = (qEt)/m

So Kinetic Energy is given as :

∴ KE = ½mv²

=> KE = ½ m {(qEt/m)}²

=> KE = (qEt)²/2m

So final answer :

 \sf{ \green{ \bold{ \huge{KE =  \dfrac{ {(qEt)}^{2} }{2m}}}}}


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