Calculate in mev the binding energy per nucleon for 12c

Asked by admin @ 26/11/2021 in Physics viewed by 263 People

What is the minimum energy (in MeV) that is required to break a nucleus of 12C (of mass 11.99671 u) into three nuclei of 4He (of mass 4.00151 u each)?

Answered by admin @ 26/11/2021

Answer:

the minimum energy that needed to break the nucleus is 1.12608 × 10^-12 J

Explanation:

The computation of the minimum energy that needed to break the nucleus is shown below:

The Change in mass is

= 11.99671 - 3 × 4.00151

= 0.00782

The Energy = mc^2

= (0.00782 × 1.6 × 10^{-27}) × (3 × 10^8)^2

= 1.12608 × 10^-12 J

Hence, the minimum energy that needed to break the nucleus is 1.12608 × 10^-12 J

The same is to be considered

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