Calculate the energy of the violet light emitted by a hydrogen atom with a wavelength of 410.1 nm.

Asked by maham237 @ 16/12/2020 in Physics viewed by 400 People

Answered by maham237 @ 16/12/2020

Answer:

$E=4.847x10^{-19}J$

Explanation:

Using the equation for energy:

$E=\frac{hc}{\lambda}$

where h is plack's constant:

$h=6.626x10^{-34}J*s$

and c is the velocity of light:

$c=3x10^8m/s$

and $\lambda$ is the wavelength of the light:

$\lambda=410.1 nm=410.1 x10^{-9}m$

Thus, the energy E:

$E=\frac{(6.626x10^{-34}J*s)(3x10^8m/s)}{410.1 x10^{-9}m}$

$E=4.847x10^{-19}J$

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