An object of height 7.5 cm

Asked by admin @ in Physics viewed by 306 People

An object of height 7.5 cm is placed at a distance of 35 cm from the

converging lens whose focal length is 15 cm. (i) what is the height of the
image formed? (ii) what is the magnification produced by the lens? (iii)
what is the nature of the image formed by the lens?

Answered by admin @


GIVEN THAT -

Height of object ( O ) = 7.5 cm

distance of object ( U ) = - 35 cm

Focal length ( F ) = + 15 cm

Distance of Image ( V ) = ?

Height of Images ( I ) = ?

Magnification ( M ) = ?

By lens formula ,

1 / F = 1 / V - 1 / U

1 / 15 = 1 / V - ( 1 / - 35 )

1 / 15 = 1 / V + 1 / 35

1 / V = 1 / 15 - 1 / 35

1 / V = ( 7 - 3 ) / 105

1 / V = 4 / 105

V = 105 / 4 = 26.25 cm

M = I / O = V / U

I / 7.5 = 26.25 / -35

I = - 0.75 x 7.5 = -5.625 cm

M = I / O = - 5.625 / 7.5 = - 0.75

Image is real inverted and diminished....

hoped so u got the ans mark me as brainellist if u like the ans ❤✌❤✌


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