A person holds a bucket of weight 60n
Asked by admin @ in Physics viewed by 304 People
A PERSON HOLDS A BUCKET OF WEIGHT 60N HE WALKS 7M ALONG HORIZONTAL AND THEN CLIMB A VERTICLE DISTANCE OF 5M THE WAORKDONE BY THE MAN WILL BE
Answered by admin @
Where, F =60N, S hori =7m , S vert =5 m
Let W1 and W2 be the work done in two cases.
Then W1=FS cos Θ =60*7*cos 90 =0
[Θ =90,because the force is vertical ]
W2 =60 *5*cos 0 =300 J
Total work done W =W1 +W2 =0+300 =300 J ANS
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