A particle projected from ground moves at angle 45

Asked by admin @ 17/08/2021 in Physics viewed by 320 People

A paRticle projected from ground move at 45 degree with horizontal one second after projection and speed is minimum two seconds after projection.The angle of projection of particle is (neglect air resistance)

Answered by admin @ 17/08/2021

X = u cos θ t and Vx = u cos θ
y = u sin θ t - 1/2 g t² abd Vy = u sin θ - g t

The horizontal component of speed Vx is always constant. So the speed is minimum when the vertical component Vy is 0.
=> u sinθ = 2 g

45° = direction of velocity of the project at time t = 1 sec.
Then Tan 45° = 1 = Vy / Vx = (u sinθ - g*1)/(u cosθ)
=> u cosθ = g
=> tan θ = 2 => θ = Tan⁻¹ 2
=> sinθ = 2/√5 and cosθ = 1/√5 and u = √5 g

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A particle projected from ground moves at angle 45

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