A mercury drop of radius 1 cm is sprayed

Asked by admin @ 20/08/2021 in Physics viewed by 270 People

a mercury drop of radius 1 cm is sprayed into 10^6 droplets of equal size. calculate energy expended. surface tension of mercury = 32× 10^-2 N/m

Answered by admin @ 20/08/2021

A mercury drop of radius 1 cm is sprayed into 10^6 droplets of equal size, the surface tension of mercury = 32× 10^-2 N/m. Calculate the energy expended.

Explanation:

From the above-given data, Let us consider 'R' as the radius of the big drop, and 'r' as the radius of the small drop.
The total volume is conserved on the formation of small drops.

Solution: 4/3 πr³ × $10^{6}$ = 4/3 πR³

The other form is ⇒ r = R × $10^{-2}$ = 0.01 cm

To calculate the energy expended, the formula is

Energy expended = Surface tension × Increase in surface area

= T × 4π(R² - $10^{6}$ r²)

= 32 × $10^{-2}$ × 4 × 3.14 [ $10^{6}$ (0.01 × $10^{-2}$ ) - ( $10^{-2}$ )²]

= 401.92 × $10^{6}$ × $10^{4}$ J

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