A golfer takes three putts to get the ball

Asked by maham237 @ 11/02/2021 in Physics viewed by 275 People

A golfer takes three putts to get the ball into the hole. The first putt displaces the ball 3.32 m north, the second 1.57 m southeast, and the third 0.718 m southwest. What is the magnitude of the displacement needed to get the ball into the hole in just one putt

Answered by maham237 @ 11/02/2021

Answer:

The answer to the question is

The magnitude of the displacement needed to get the ball into the hole in just one putt is 1.746m in the direction of 23.41° north east

Explanation:

With trigonometric relation and the attached diagram we have

From the diagram the location of the hole is 3.32m- (1.57 cos45 +0.78co45)m North and

1.57sin 45 – 0.78 sin 45 meters west

1.658m north and

0.55m east

Thus the direction of the hole is 26.41 degrees

North east

The magbitude of the displacement is displacement is gotten from the relation diplacement of x and y =√(x²+y²)

$\sqrt{1.658^{2} +0.55^{2} } = 1.746 m$ ∠26.41°

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