A ball with a horizontal speed of 1.25 m/s rolls off a bench 1.00 m above the floor.

Asked by maham237 @ 25/12/2020 in Physics viewed by 308 People

A ball with a horizontal speed of 1.25m/s rolls off a bench 1.00m above the floor.
Part A
How long will it take the ball to hit the floor?
Part B
How far from a point on the floor directly below the edge of the bench will the ball land?

Answered by maham237 @ 25/12/2020

Answer:

Part A: Time = 0.45 s

Part B: Horizontal distance = 0.5625 m

Explanation:

Part A:

As the ball with a horizontal speed of 1.25 m/s rolls off a bench 1.00 m above the floor, it follow the projectile path.

Projectile motion is a two dimensional motion and the path followed by projectile motion is called projectile path.

Given data:

horizontal velocity = v₍ₓ₎ = 1.25 m/s

vertical velocity = v₍ₙ₎ = 0 m/s

Height = h = 1 m

From 2nd equation of motion

h = v₍ₙ₎t + 0.5 gt²

1 = 0 + 0.5(9.81)t²

2 = 9.81 t²

t = √(0.2)

t = 0.45 s

Part B:

In projectile motion, horizontal component of velocity remain same,

So there is no acceleration in horizontal direction.

We can use the following formula

Horizontal distance = R = v₍ₓ₎t

R = 1.25 × 0.45

R = 0.5625 m

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