A 1500 kg car skids to a halt on a wet road where μk = 0.53.
Asked by maham237 @ in Physics viewed by 373 People
how fast was the car traveling if it leaves 66-m-long skid marks?
Asked by maham237 @ in Physics viewed by 373 People
how fast was the car traveling if it leaves 66-m-long skid marks?
Answered by maham237 @
We got coefficient of
friction uk = 0.51
Mass m = 1500 kg
normal force on the car = weight of the car = 1500 * 9.8 N =
14700 N
and the force of friction on the car, f = uk * normal force =
0.51 * 14700 N = 7497 N
taking Acceleration a = -f/m = -7497/1500 = -4.998 m/s^2
Displacement s = 66 m
Final velocity v = 0
Initial velocity u = ?
v^2 = u^2 + 2as
0 = u^2 - 2 * 4.998 * 66
u = 25.69 m/s
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