Which equation is y = –6x2 + 3x + 2 rewritten in vertex form?


Asked by maham237 @ in Mathematics viewed by 461 People

Answered by maham237 @



we have

 y = -6x^{2} + 3x + 2

we know that

the vertex form of the vertical parabola equation is equal to

 y=a(x-h)^{2} +k

where

(h,k) is the vertex of the parabola

To find the equation rewritten in vertex form let's factor the equation

Factor the leading coefficient

 y = -6(x^{2} - 0.5x) + 2

Complete the square. Remember to balance the equation by adding the same constants to each side

 y = -6(x^{2} - 0.5x+0.0625-0.0625) + 2

 y = -6(x^{2} - 0.5x+0.0625) + 2 +0.375

 y = -6(x^{2} - 0.5x+0.0625) + 2.375

Rewrite as perfect squares

 y = -6(x-0.25)^{2} + 2.375

therefore

the answer is

 y = -6(x-0.25)^{2} + 2.375


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