What is the range of the function f(x) = 3x2 + 6x – 8?

Asked by maham237 @ 25/12/2020 in Mathematics viewed by 387 People

What is the range of the function f(x) = 3x2 + 6x – 8?
{y|y ≥ –1}

{y|y ≤ –1}

{y|y ≥ –11}

{y|y ≤ –11}

Answered by maham237 @ 25/12/2020

F(x) is a quadratic equation with the x-side squared and a is positive which means that the graph of the function is a parabola facing up. The range of f(x) is given by {y|y ≥ k}, where k is the y-coordinate of the vertex.
$f(x)=3 x^{2} +6x-8$ , written in vertex form is
$y=3 (x+1)^{2} -11$ , where (h, k) = (-1, -11)
Therefore, range ={y|y ≥ -11}

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