What are the zeros of the quadratic function f(x) = 2x2 + 16x – 9?

Asked by maham237 @ 22/12/2020 in Mathematics viewed by 399 People

Answered by maham237 @ 22/12/2020

F(x)=0=2*x^2+16*x-9;
2*x^2+16*x-9=0
x= -8/2+(8^2-2*(-9))^(1/2)/2 and x=-8/2-(8^2-2*(-9))^(1/2)/2;
x= -4+ \sqrt{64+18} /2 and x=-4- \sqrt{64+18} /2;
x= -4+ \sqrt{\frac{41}{2}} and x= -4- \sqrt{\frac{41}{2}} .
f(x)=0, if x= -4+ \sqrt{\frac{41}{2}} and x= -4- \sqrt{\frac{41}{2}} .
Answer: x= -4+ \sqrt{\frac{41}{2}} and x= -4- \sqrt{\frac{41}{2}} .

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Asked by maham237 @ 26/12/2020 in Mathematics viewed by 314 persons

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Asked by maham237 @ 25/12/2020 in Mathematics viewed by 337 persons

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Asked by maham237 @ 23/12/2020 in Mathematics viewed by 321 persons

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