Using the quadratic formula to solve 2x2 = 4x – 7, what are the values of x?


Asked by wiki @ in Mathematics viewed by 350 People

Answered by wiki @


For this case we have the following quadratic equation:

 2x ^ 2 = 4x - 7

Rewriting the equation we have:

2x ^ 2 - 4x + 7 = 0

From here, we have:

a=2 b = -4c = 7

Substituting values in the quadratic equation we have:

 x = \frac{-b+/-\sqrt{b^2-4ac}}{2a}

 x = \frac{-(-4)+/-\sqrt{(-4)^2-4(2)(7)}}{2(2)}

Rewriting the equation we have:

 x = \frac{4+/-\sqrt{16-56}}{4}

 x = \frac{4+/-\sqrt{-40}}{4}

 x = \frac{4+/-\sqrt{-4*10}}{4}

 x = \frac{4+/-2i\sqrt{*10}}{4}

 x = \frac{2+/-i\sqrt{*10}}{2}

Answer:

The values of x are given by:

 x = \frac{2+i\sqrt{*10}}{2}

 x = \frac{2-i\sqrt{*10}}{2}

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