Solving quadratic equations by using the quadratic formula 9 5


Asked by admin @ in Mathematics viewed by 371 People


Solve the following quadratic equation using the quadratic formula.

5x^2 − 8x + 5 = 0
Write the solutions in the following form, where r, s, and t are integers, and the fractions are in simplest form.
x = r − si/t,x = r + si/t

Answered by admin @



Quadratic equations can be solved using several methods; one of them, is by using quadratic formula

The solution to 5x^2 - 8x + 5 = 0 is: x = \frac{4 + 3i}{5}, x = \frac{4 - 3i}{5}

The equation is given as:

5x^2 - 8x + 5 = 0

The quadratic formula is:

x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}

In the given equation;

a = 5\\b = -8\\c = 5

So:

x = \frac{-(-8) \± \sqrt{(-8)^2 - 4 \times 5 \times 5}}{2 \times 5}

x = \frac{8 \± \sqrt{-36}}{10}

Expand

x = \frac{8 \± \sqrt{36} \times \sqrt{-1}}{10}

x = \frac{8 \± 6 \times \sqrt{-1}}{10}

In complex numbers;

i = \sqrt{-1}

So, we have:

x = \frac{8 \± 6 \times i}{10}

x = \frac{8 \± 6i}{10}

Simplify

x = \frac{4 \± 3i}{5}

Split

x = \frac{4 + 3i}{5}, x = \frac{4 - 3i}{5}

Hence, the solution to 5x^2 - 8x + 5 = 0 is: x = \frac{4 + 3i}{5}, x = \frac{4 - 3i}{5}

Read more about quadratic formulas at:

brainly.com/question/9701183


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